putin ajutor va rog <table width=80% align=\"center\"> <tr> <td class=subTitle>Meci</td><td class=subTitle>Rezultat</td><td class=subTitle>1</td><td class=subTitle>X</td><td class=subTitle>2</td></tr> <?php $selectr = mysql_query("SELECT * FROM `[meciuri]`"); while($meci = mysql_...

chiar nu exista nici o rezolvare ? Parse error: syntax error, unexpected '&' in /home/public_html/adp.php on line 119 ($_FILES['img']['type'] == &quot;image/png&quot || ($_FILES['img']['type'] == &quot;image/jpeg&quot) {

Codul : <?PHP if (isset($_POST['submit'])) { $descriere = $gegeven["descriere"]; $insert = "INSERT INTO `[parteneri]`(`site`,`link`,`descriere`,`rank`,`rank1`) values('{$_POST['site']}','{$_POST['link']}','{$_POST['descriere']&...

cand aduga codul de mai sus in <?PHP if (isset($_POST['submit'])) { $descriere = $gegeven["descriere"]; $insert = "INSERT INTO `[parteneri]`(`site`,`link`,`descriere`,`rank`,`rank1`) values('{$_POST['site']}','{$_POST['link']}','
...

in codul de mai jos am nevoie de un pic de ajutor sa fac ceva sa mearag sa intorduc o imagine in baza de date <?PHP if (isset($_POST['submit'])) { $descriere = $gegeven["descriere"]; $insert = "INSERT INTO `[parteneri]`(`site`,`link`,`descriere`,`rank`,`rank1`...

Din <? while($ticket = mysql_fetch_object($object)){ ?> Am facut <?php while($ticket[]=mysql_fetch_array($object)); ?> Da Eroare Parse error: syntax error, unexpected '}' in /home/public_html/abc.php on line 204 La line 204 am asa <? } ?> Iar daca sterg...

mersi ispas acum functioneaza

<?php // Parametri SQL $_mysql_host="localhost"; // Host baza de date $_mysql_db=" "; // Baza de date $_mysql_user=" "; // User baza de date $_mysql_password=" "; // Parola baza de date $conexiune = mysql_connect($_mysql_host,$_mysql_user,$_mysql_password...